Semantics of pre- and postfix “++” operator in Java [duplicate]

Answer 1

When we use post or pre increment operator it increases the value.

Post increment operator (i++) assigns the value first, then increments it. Pre increment operator (++i) increments first then assigns the value. They both behave like this :

int i=0;
i=i++;
System.out.println(i); //1
i=++i;
System.ou.println(i); //1

Answer 2

When this code runs:

public static void main(String[] args) {
    int i = 0;                //i=0;
    System.out.print(++i);    // increments i to i=1, and prints i
    System.out.print(i++);    // prints i and then increments it to i=2
    System.out.print(i);      // prints i, i.e. 2
}

Answer 3

Simply;

In post increment, the increment is done after the variable is read.

In pre increment, the variable value is incremented first, then used in the expression.

Answer 4

Your snippet it's translated as

int i = 0;
i = i + 1; // 1
System.out.print(i); // 1
System.out.print(i); // 1
i = i + 1; // 2
System.out.print(i); // 2

That's why the final result it's a 2.

++i it's incrementing the variable before being called by the print method and i++ it's incrementing the variable after the method execution.

Answer 5

i is initially 0, then it is pre-incremented and printed so you have the first 1, then it is printed again and you have the second 1, then post-incremented, then printed for the last time and you have the 2

Answer 6

i++ is the post-increment operator, which has expression value the old value of i, but a side-effect of incrementing i. The value is 1, but it leaves i changed to 2.