How to reading XML from a URL in Android

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心在旅途
心在旅途 2021-01-21 09:58

I want to read a XML document from a URL:

public void DownloadXmlFile() throws IOException{
        //TODO
        String url = \"http://api.m1858.com/coursebook         


        
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  • 2021-01-21 10:43

    there are two step for read data from server...

    1.Make a HTTP request to get the data from the webservice 2.Parse a XML document and read the contents

    try 
        {
    
            URL url = new URL("http://www.w3schools.com/xml/note.xml");
    
            DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
            DocumentBuilder db = dbf.newDocumentBuilder();
            Document doc = db.parse(new InputSource(url.openStream()));
            doc.getDocumentElement().normalize();
    
            NodeList nodeList = doc.getElementsByTagName("note");
            /** Assign textview array lenght by arraylist size */
    
    
            to = new TextView[nodeList.getLength()];
            from = new TextView[nodeList.getLength()];
            heading = new TextView[nodeList.getLength()];
            body = new TextView[nodeList.getLength()];
    
    
    
            for (int i = 0; i < nodeList.getLength(); i++) 
            {
                Node node = nodeList.item(i);
    
                to[i] = new TextView(this);
                from[i] = new TextView(this);
                body[i] = new TextView(this);
                heading[i] = new TextView(this);
    
                Element fstElmnt = (Element) node;
                NodeList toList = fstElmnt.getElementsByTagName("to");
                Element nameElement = (Element) toList.item(0);
                toList = nameElement.getChildNodes();
                to[i].setText("To = "+ ((Node) toList.item(0)).getNodeValue());
    
                NodeList fromList = fstElmnt.getElementsByTagName("from");
                Element fromElement = (Element) fromList.item(0);
                fromList = fromElement.getChildNodes();
                from[i].setText("from = "+ ((Node) fromList.item(0)).getNodeValue());
    
                NodeList headingList = fstElmnt.getElementsByTagName("heading");
                Element headingElement = (Element) headingList.item(0);
                headingList = headingElement.getChildNodes();
                heading[i].setText("heading = "+ ((Node) headingList.item(0)).getNodeValue());
    
    
                NodeList bodyList = fstElmnt.getElementsByTagName("body");
                Element bodyElement = (Element) bodyList.item(0);
                bodyList = bodyElement.getChildNodes();
                body[i].setText("body = "+ ((Node) bodyList.item(0)).getNodeValue());
    
                layout.addView(to[i]);
                layout.addView(from[i]);
                layout.addView(heading[i]);
                layout.addView(body[i]);
    
            }
        } 
        catch (Exception e) 
        {
            System.out.println("XML Pasing Excpetion = " + e);
        }
    
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  • 2021-01-21 10:53

    This is not an XML Problem its a Strict Mode Problem. You should'nt do time intensiv things in Gui Thread, do it in a own Thread.

    • Blogpost with introduction
    • Developers API infos
    • BestPracties

    However, you can disable it, but you shouldt ;) see here

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  • 2021-01-21 10:53

    Why you don't google or look for the error here on stackoverflow? It's full of answers...

    You have to extend an AsyncTask to avoid the blocking of the GUI and do this kind of operation (as downloading or parsing stuff) in background.

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