how can I read each line of a xls file with pausing

Question

I have a xls file on my desktop in mac which has many row (each row consists of a word). what I want is to show each line for 3 minutes in terminal. note that the version of xls

Answer 1

do it in this way on Mac

import time
import pandas as pd
import os
import xlrd
# at first I try to know how many rows and how many columns I have 
workbook = xlrd.open_workbook('myfile.xls')
for sheet in workbook.sheets():
    for row in range(sheet.nrows):
        for column in range(sheet.ncols):
            os.system('clear')
            print "value::: ", sheet.cell(row,column).value
            time.sleep(5.5)    # pause 5.5 seconds

Answer 2

If I understand this correctly, your problem is that you want a line to show up on the terminal for some time, but get hidden when the next one shows up. You can try this for python3 (see the accepted answer for earlier versions):

import time
import subprocess

import pandas as pd
import xlrd
# at first I try to know how many rows and how many columns I have 
workbook = xlrd.open_workbook('myfile.xls')
for sheet in workbook.sheets():
    for row in range(sheet.nrows):
        for column in range(sheet.ncols):
            subprocess.run(["clear"])
            print "row::::: ", row
            print "column:: ", column
            print "value::: ", sheet.cell(row,column).value
            time.sleep(5.5)    # pause 5.5 seconds

clear is generally for Unix though, if it does not work on a Mac, this answer can be helpful.