Python argv taking wild card path

Question

I run my script with doc1/*.png as first argument, but it gets converted to doc1/image1.png.

How can I let Python see the exact argument?<

Answer 1

On most linux shells (bash, sh, fish,...), the asterisk is handled by the shell. The fact that the * is converted to a list of files is already done at the shell level.

If you write:

python file.py doc/*.png

The shell itself will translate doc/*.png into "doc/1.png" "doc/2.png" (so a list of .png files it finds in the doc directory.

You should use quotes to pass the asterisk, like:

python file.py 'doc/*.png'

The standard Windows shell does not do wildcards for file names.

Answer 2

As @Jean-François Fabre sais, it is possible to use wildcards on windows using glob module.

import glob
paths = glob.glob('C:\path\with\wildcard.*')