Assign the result of a loop to a variable in Python

Question

Consider a list I want to parse using a for :

friends = [\"Joe\", \"Zoe\", \"Brad\", \"Angelina\", \"Zuki\", \"Thandi\", \"Paris\"]
for i in fri         


        

Answer 1

If I understand well, you'd like to dynamically create variables. Here it is.

from collections import OrderedDict

friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
d = OrderedDict()
for idx, value in enumerate(friends):
    key = 'var' + str(idx)
    d[key] = value 

print(d)
# Output
OrderedDict([('var0', 'Joe'), ('var1', 'Zoe'), ('var2', 'Brad'), ('var3', 'Angelina'), ('var4', 'Zuki'), ('var5', 'Thandi'), ('var6', 'Paris')])

Answer 2

I also have this question, this is how I managed to solve it somewhat:

    friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]

    new_friends = ' '.join([x for x in friends])

    print(new_friends)

Will return:

    Joe Zoe Brad Angelina Zuki Thandi Paris

Answer 3

If you want to join the values in friends into a comma-separated string, that would be

s = ','.join(friends)

If you want to include quotes around the names, maybe something like

s = ','.join(['"{0}"'.format(x) for x in friends])

Answer 4

var = ''
friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
for i in friends:
    var=i 

if list and loop are in function then declare var as global

global var

in starting of function

Answer 5

Try this at the end of the loop:

the_variable = the_variable + i

However, if you are to do this, you should add a space to the end of every item in the dictionary, otherwise it will output:

JoeZoeBradAngelinaZukiThandiParis

Answer 6

I would use a dictionary instead, as I too spent a while looking into this, and determined that a dictionary would be easy enough.

    friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
    dict= {}
    for i in friends:
       dict[i] = i

    print(dict)
    print(dict['Zuki'])
    dict['Zuki'] = "Tim Smith"

    print(dict['Zuki'])

The Other option would be to just call the number:

    print(friends[0])

As for automatic assignment I haven't found a way to do it.