Can anyone of you help in converting the date from 20150101 to abbreviated form Jan-2015 ?
I tried the below method.
x = 20
You can use a combination of strptime to convert the string to a date object and format to format to what you want:
date = "20150101"
format(strptime(date,format="%Y%m%d"),"%b-%Y")
Using lubridate and zoo packages:
library(lubridate)
library(zoo)
x <- "20150101"
as.yearmon(as.Date(ymd(x)))
[1] "jan 2015"
There are two problems with the code in the question:
the input format is specified as "%b-%y" but should be
"%y%m"
we wish to use as.yearmon.character here rather than
as.yearmon.numeric so the input should be converted to
"character"
Therefore, try this:
library(zoo)
ym <- as.yearmon(as.character(20150101), "%Y%m")
giving:
> ym
[1] "Jan 2015"
Note that "yearmon" objects are internally stored as year + fraction where fraction is 0 for Jan, 1/12 for Feb, ..., 11/12 for Dec. Externally they are rendered as an abbreviated month followed by a space and the year as shown.
The above may be sufficient but if not to convert it to a character string with format "%b-%y" or "%b-%Y" use format:
format(ym, "%b-%y")
## [1] "Jan-15"
format(ym, "%b-%Y")
## [1] "Jan-2015"