I have this snippet.
public final class StackOverflow{
class MyException extends Throwable{
}
private void a(){
try{
}catch(MyExceptio
It is explained in the Java Language Specification (emphasis in bold):
It is a compile-time error if a
catchclause can catch checked exception class E1 and it is not the case that thetryblock corresponding to thecatchclause can throw a checked exception class that is a subclass or superclass of E1, unless E1 isExceptionor a superclass ofException.
I guess the rationale behind this is that: MyException is indeed a checked exception. However, unchecked exceptions also extend Exception (transitive inheritance from RuntimeException), so having a catch include the Exception class is excluded from the exception analysis done by the compiler.
Exception extends from RuntimeException will considered as uncheched exception, so it's ok:
class MyException extends RuntimeException { }
try {
...
} catch (MyException e) {
}
Your exception extends from Throwable, so it is cheched exception. Since the compiler noticed that it is never thrown, so the compile fails.