Need regular expression for checking at least 3 uppercase, 3 lowercase, 3 digits and 3 special character

Question

Need regular expression for checking at least 3 uppercase, 3 lowercase, 3 digits and 3 special character any where in string.

I have tried /^(?=.*[^A-Za-z0-9]

Answer 1

/^(?=(.*[^A-Za-z0-9]){3,})(?=(.*[A-Z]){3,})(?=(.*\d){3,})(?=.*[a-z]){3,}).+/

So you were close.

Answer 2

Both of the other answers fail for a string which doesn't match the "at least 3 lowercase" requirement. Using Bohemian's answer but supporting that case gives the following regex:

^(?=(.*[^A-Za-z0-9]){3})(?=(.*[A-Z]){3})(?=(.*[a-z]){3})(?=(.*\d){3}).+

Answer 3

You were close: you need to bracket the .* with the character classes in your look aheads:

^(?=(.*[^A-Za-z0-9]){3})(?=(.*[A-Z]){3})(?=(.*\d){3}).+

The reason this works is that the character types may not be adjacent, eg 3 digits might be a1b2c3, hence the .* to allow other intervening character types.

Note that you don't need the open-ended quantifiers. eg (.*\d){3} is sufficient to assert that there are at least 3 digits - ie not ...{3,}

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And a final note: those leading/trailing slashes have nothing whatsoever to do with regular expressions - they are an application language artefact. It makes questions and answers clearer and more useful to more people if they are omitted.