Perl shift operator simple question

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离开以前 2021-01-19 03:33

What\'s the purpose of the following two lines of perl??

my $host = shift || \'localhost\';
my $port = shift || 200;

That should return loc

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  • 2021-01-19 03:59

    What this piece of code is, is a way to provide default values for $host and $port. It will typically be at the start of a script or a subroutine, and take values from @ARGV and @_ respectively.

    That should return localhost and port 10.

    No, the || operator is a short circuiting OR, which means that if the LHS operand returns a true value, the RHS operand is ignored. Basically, it means this (and ONLY this): "choose the left hand side value if it is true, otherwise choose the right hand side value."

    shift ARRAY will return the first value of ARRAY, or:

    If ARRAY is omitted, shifts the @_ array within the lexical scope of subroutines and formats, and the @ARGV array outside a subroutine and also within the lexical scopes established by the eval STRING , BEGIN {} , INIT {} , CHECK {} , UNITCHECK {} and END {} constructs.

    Quoted from http://perldoc.perl.org/functions/shift.html

    Also, of course, shift removes the value from the array that is shifted. Therefore you can have two shift in a row like this, for very convenient argument handling.

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  • 2021-01-19 04:01

    If you use shift, always put the array on it. I've seen experience Perl programmers forget that outside a subroutine, shift works on @ARGV. The more things a programmer has to remember at the same time, the more likely he is to make an error.

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  • 2021-01-19 04:02

    If no argument is provided, shift will shift @ARGV outside a subroutine and @_ inside a subroutine – that is the argument array passed to either the main program or the subroutine.

    In your case, $host is assigned the first element of @ARGV (or @_, if the code is inside a sub) or 'localhost', if the element is false.

    This is a very common Perl idiom.

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  • 2021-01-19 04:06

    shift return the first element of an array and removes it from the array. Like pop, but from the other end.

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  • 2021-01-19 04:16

    The first line shifts from either @_ or @ARGV (depending on where you are in the code), or in the absence of any contents in @_/@ARGV, assigns localhost to $host.

    The second one should be self-explanatory now.

    Have a look at the shift documentation for details.

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