I have a QMenu with many submenus. These are dynamically created i.e. the names menus come from a db and created in a loop. Now i wanted to fire the same slot triggered() or
After adding the QAction to the menu, you only have to connect QMenu to the slot. You don't connect each action individually to the slot:
for(int j=0; j<channelTypes[i].getNumChannels() ; j++){
ch_name = <name from the database for the channel j>;
QAction *subMenuAct = subMenu->addAction(tr(ch_name));
subMenuAct->setData(ch_name);
}
connect(subMenu, SIGNAL(triggered(QAction *)),
this, SLOT(playChannel(QAction *)), Qt::UniqueConnection);
As I don't know how you if you delete subMenu each time the dynamic menu is filled, the Qt::UniqueConnection ensure that the slot won't be reconnected multiple times.
for(int j=0; j<channelTypes[i].getNumChannels() ; j++){
ch_name = <name from the database for the channel j>;
QAction *subMenuAct = subMenu->addAction(tr(ch_name));
connect(subMenuAct, SIGNAL(triggered()), signalMapper, SLOT(map()));
signalMapper->setMapping(subMenuAct, ch_name);
}
connect(signalMapper, SIGNAL(mapped(QString)), this, SLOT(playChannel(QString)));
And for that case, the slot playChannel should accept a QString instead of a QAction*.