Is any() evaluated lazily?

Question

I am writing a script in which i have to test numbers against a number of conditions. If any of the conditions are met i want to return True an

Answer 1

Yes, any() and all() short-circuit, aborting as soon as the outcome is clear: See the docs:

all(iterable)

Return True if all elements of the iterable are true (or if the iterable is empty). Equivalent to:

def all(iterable):
    for element in iterable:
        if not element:
            return False
    return True

any(iterable)

Return True if any element of the iterable is true. If the iterable is empty, return False. Equivalent to:

def any(iterable):
    for element in iterable:
        if element:
            return True
    return False