javascript fizzbuzz switch statement

Question

I\'m currently taking the code academy course on Javascript and I\'m stuck on the FizzBuzz task. I need to count from 1-20 and if the number is divisible by 3 print fizz, by

Answer 1

Here's what made it clear for me, might help : It's a misinterpretation of what switch (x){} means.

It doesn't mean : "whenever whatever I put inbetween those brackets is true, when the value of x changes."
It means : "whenever x EQUALS what I put between those brackets"

So, in our case, x NEVER equals x%3===0 or any of the other cases, that doesn't even mean anything. x just equals x all the time. That's why the machine just ignores the instruction. You are not redefining x with the switch function. And what you put inbetween the brackets describes x and x only, not anything related to x.

In short :
With if/else you can describe any condition.
With switch you can only describe the different values taken by the variable x.

Answer 2

Not to too my own horn but this is much cleaner:

var numbers = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20];
for (var i = 1; i <= numbers.length; i++) {  
    if (i % 15 === 0) {
        console.log("FizzBuzz");
    } else if (i % 5 === 0) {
        console.log("Buzz");
    } else if (i % 3 === 0) {
        console.log("Fizz");
    } else {
        console.log(i);
    }
};