x86: register operation as memory content and memory address?

Question

register ---> memory address --> memory content

memory address --> memory content

is the above model correct??

and, if it is can you suggest if i am

Answer 1

movl %eax, %ebx --> moves the content of register %eax into register %ebx. It is irrelevant what %eax contains.

movl (%eax),%ebx --> moves the content of the memory address contained in %eax into register %ebx

movl value, %eax --> moves content of memory address value into register %eax.

movl %eax, val --> moves content of register %eax to memory address val

movl $val, %eax --> moves the constant $val into the register %eax

movl %eax, $val --> impossible. You cannot move something into a constant value.

movl (%eax), val --> impossible. You must use a register as intermediate:

movl (%eax),%eax
movl %eax,val    ; or use another intermediate register than %eax                    

mov (%eax), $val --> impossible. You cannot move something into a constant value.

mov $val, (%eax) --> move constant value $val into memory address contained in %eax.