sql order by with an inner select clause and group by rollup

Question

My query looks like below with the foll. output

Current Output

Role            Cases prepped % Completed    
State Member 1  10    5       50%
State Me         


        

Answer 1

You could do something like this. I don't have your input data, so I used SCOTT.EMP instead.

Notice a few things. I grouped by JOB, and I used GROUPING(JOB) both in SELECT (to add the label TOTAL for the summary row) and in ORDER BY. Since I reuse the column name JOB in SELECT (for the output column), in ORDER BY I must be careful to qualify the column name JOB (to make it clear I am referring to the input table column, not to the column in SELECT - which would be the default if column names in ORDER BY were not qualified). The need to qualify column names in ORDER BY, then, forced me to alias the table in the FROM clause (otherwise I would have had to carry the full table name everywhere).

Using the GROUPING function in SELECT (rather than NVL) is particularly important if JOB can be null. You don't want the group for null job to be labeled TOTAL - you only want that for the rollup row. This point confuses even a lot of very advanced programmers.

I show how you can "manually" decide the order: PRESIDENT first, then MANAGER, and then all other jobs (ordered alphabetically). If you have the order of priority saved somewhere, for example in a table, you can join to that table and use the ordering column instead of the "manual" CASE expression in my query.

select case grouping(job) when 0 then job else 'TOTAL' end as job
     , sum(sal) as total_salary
from   scott.emp e
group  by rollup(job)
order  by grouping(e.job)       -- to get the total in the last row
        , case e.job when 'PRESIDENT' then 1 when 'MANAGER' then 2 end
        , e.job
;

JOB       TOTAL_SALARY
--------- ------------
PRESIDENT         5000
MANAGER           8275
ANALYST           6000
CLERK             4150
SALESMAN          5600
TOTAL            29025