To illustrate the question check the following code:
class MyDescriptor(object):
def __get__(self, obj, type=None):
print \"get\", self, obj, type
To answer your second question, where is _v?
Your version of the descriptor keeps _v in the descriptor itself. Each instance of the descriptor (the class-level instance SomeClass1, and all of the object-level instances in objects of class SomeClass2 will have distinct values of _v.
Look at this version. This version updates the object associated with the descriptor. This means the object (SomeClass1 or x2) will contain the attribute _v.
class MyDescriptor(object):
def __get__(self, obj, type=None):
print "get", self, obj, type
return obj._v
def __set__(self, obj, value):
obj._v = value
print "set", self, obj, value
You should read this and this.
It overwrites the function because you didn't overload the __set__ and __get__ functions of SomeClass but of MyDescriptor class. Maybe you wanted for SomeClass to inherit MyDescriptor? SomeClass1 prints the "get" and "set" output because it's a static method AFAIK. For details read the upper links.
I found _v of x1: It is in SomeClass1.__dict__['m']._v
For the version suggested by S.Lott within the other answer: _v is in x1._v