Javascript Regex match everything after last occurrence of string

Question

I am trying to match everything after (but not including!) the last occurrence of a string in JavaScript.

The search, for example, is:

[quote=\"use         


        

Answer 1

One option would be to match everything up until the last [/quote], and then get anything following it. (example)

/.*\[\/quote\](.*)$/i

This works since .* is inherently greedy, and it will match every up until the last \[\/quote\].

Based on the string you provided, this would be the first capturing group match:

\nThis is all the text I\'m wirting about myself.\n\nLook at me ma. Javascript.

But since your string contains new lines, and . doesn't match newlines, you could use [\s\S] in place of . in order to match anything.

Updated Example

/[\s\S]*\[\/quote\]([\s\S]*)$/i

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You could also avoid regex and use the .lastIndexOf() method along with .slice():

Updated Example

var match = '[\/quote]';
var textAfterLastQuote = str.slice(str.lastIndexOf(match) + match.length);
document.getElementById('res').innerHTML = "Results: " + textAfterLastQuote;

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Alternatively, you could also use .split() and then get the last value in the array:

Updated Example

var textAfterLastQuote = str.split('[\/quote]').pop();
document.getElementById('res').innerHTML = "Results: " + textAfterLastQuote;