take the mean of rows in a matrix r

Question

I have the following matrix of depth and temperature data (855 rows, 2 col) and would like to take the mean of every 3 rows within each column. For example:

Answer 1

Use rollapply function from zoo package. See ?rollapply for more details.

library(zoo)
rollapply(matrix[,1], width=3, mean, by=3)  

Example:

> set.seed(1)
> Data <- matrix(rnorm(30, 100, 50), ncol=2)  # some random data
> rollapply(Data[,1], width=3, mean, by=3)  
[1]  78.69268 118.40534 130.02559 126.60393  71.48317
> # you could check this out by doing some verification as in:
> mean(Data[1:3, 1])
[1] 78.69268
> mean(Data[4:6, 1])
[1] 118.4053
> mean(Data[7:9, 1]) # and so on ...
[1] 130.0256

If you want the mean for all columns in your matrix, then just add by.column=TRUE in the rollapply call:

> rollapply(Data, width=3, mean, by=3, by.colum=TRUE)
          [,1]      [,2]
[1,]  78.69268 114.71187
[2,] 118.40534 138.90166
[3,] 130.02559  81.12249
[4,] 126.60393 106.79836
[5,]  71.48317  74.48399

Answer 2

I really like the 'rollapply' function for this, because its syntax closely matches what you're trying to do. However, I thought I would contribute, for posterity, how you would approach this problem with the 'plyr' package.

Note: You could do this all in one statement, but I've broken it up to make it easier to understand.

Step 1: Set up your data to have a sorting variable.

data.plyr <- data.frame(test, group=floor((1:nrow(test)-1)/3)+1)

I've just added a column 'group' that assigns a group number to every three columns. The two matrix columns are now 'X1' and 'X2' by default.

Step 2: Run the 'colMeans' function for each group.

library(plyr)
ddply(data.plyr, .(group), colMeans)

For this specific question, I think the 'plyr' package is sub-optimal, but it's worth noting the method for future reference. The 'apply' family and 'rollapply' functions work best with continuity and consistency in the data. In applications where you want more flexibility, the 'plyr' family functions are useful to have in your toolbox.

Answer 3

Try to use tapply and apply:

R > f <- rep(c(1:3), each = 3)
R > f
[1] 1 1 1 2 2 2 3 3 3
R > x <- matrix(1:27, 9, 3)
R > x
      [,1] [,2] [,3]
 [1,]    1   10   19
 [2,]    2   11   20
 [3,]    3   12   21
 [4,]    4   13   22
 [5,]    5   14   23
 [6,]    6   15   24
 [7,]    7   16   25
 [8,]    8   17   26
 [9,]    9   18   27
R > apply(x, 2, function(t) tapply(t, f, mean))
  [,1] [,2] [,3]
1    2   11   20
2    5   14   23
3    8   17   26