So I\'ve found similar resources that address how to do this in SQL, like this: Duplicating records to fill gap between dates
I understand that BigQuery may not be t
I need to generate a table that has all the dates within a given range, but I'm having a hard time understanding if this can be done. Any ideas?
SELECT DATE(DATE_ADD(TIMESTAMP("2016-08-01"), pos - 1, "DAY")) AS DAY
FROM (
SELECT ROW_NUMBER() OVER() AS pos, *
FROM (FLATTEN((
SELECT SPLIT(RPAD('', 1 + DATEDIFF(TIMESTAMP("2016-08-07"), TIMESTAMP("2016-08-01")), '.'),'') AS h
FROM (SELECT NULL)),h
)))
How can I build a query within Google BigQuery that yields an output like the one below? A value at a given date is repeated until the next change for the dates in between
See example below
SELECT
MODIFY_DATE,
MAX(SKU_TEMP) OVER(PARTITION BY grp) AS SKU,
MAX(STORE_TEMP) OVER(PARTITION BY grp) AS STORE,
MAX(STOCK_ON_HAND_TEMP) OVER(PARTITION BY grp) AS STOCK_ON_HAND,
FROM (
SELECT
DAY AS MODIFY_DATE, SKU AS SKU_TEMP, STORE AS STORE_TEMP, STOCK_ON_HAND AS STOCK_ON_HAND_TEMP,
COUNT(SKU) OVER(ORDER BY DAY ASC ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS grp,
FROM (
SELECT DATE(DATE_ADD(TIMESTAMP("2016-08-01"), pos - 1, "DAY")) AS DAY
FROM (
SELECT ROW_NUMBER() OVER() AS pos, *
FROM (FLATTEN((
SELECT SPLIT(RPAD('', 1 + DATEDIFF(TIMESTAMP("2016-08-07"), TIMESTAMP("2016-08-01")), '.'),'') AS h
FROM (SELECT NULL)),h
)))
) AS DATES
LEFT JOIN (
SELECT DATE(MODIFY_DATE) AS MODIFY_DATE, SKU, STORE, STOCK_ON_HAND
FROM
(SELECT "2016-08-01" AS MODIFY_DATE, "1120010" AS SKU, 21 AS STORE, 75 AS STOCK_ON_HAND),
(SELECT "2016-08-05" AS MODIFY_DATE, "1120010" AS SKU, 22 AS STORE, 100 AS STOCK_ON_HAND),
(SELECT "2016-08-07" AS MODIFY_DATE, "1120011" AS SKU, 23 AS STORE, 40 AS STOCK_ON_HAND),
) AS TABLE_WITH_GAPS
ON TABLE_WITH_GAPS.MODIFY_DATE = DATES.DAY
)
ORDER BY MODIFY_DATE