Casting a char array to be of type struct *

Question

In the code below could somebody perhaps explain what is happening on the line struct ether_header *eh = (struct ether_header *) sendbuf;? I understand that it

Answer 1

But how can you do this isif sendbuf is a char array?

Code should not do this.

Casting a pointer to a type that was not originally a valid pointer for that type is undefined behavior (UB).

char sendbuf[BUF_SIZ];
struct ether_header *eh = (struct ether_header *) sendbuf;  // UB

At a minimum, consider if struct ether_header had an alignment requirement to be an even address and sendbuf[] began on an odd address. The assignment may kill the program.

A 2nd concern is what unposted code might later do with sendbuf[] and eh which can violating strict aliasing rule @Andrew Henle.

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A better approach is to use a union. Now the members are aligned and the union handles the strict aliasing rule.

union {
  char sendbuf[BUF_SIZ];
  struct ether_header eh;
} u;

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Also why would you do this?

To allow access to the data from 2 data type perspectives. Perhaps to make a data dump of u.

Answer 2

The line char sendbuf[BUF_SIZ] allocates a block of chars (i.e. bytes on most systems) and the cast struct ether_header *eh = (struct ether_header *) sendbuf says that you explicitly want to treat this as a struct ether_header type. There are no significant instructions from this cast, aside from (possibly) setting a CPU register.

You'll end up with two pointers to the same block of memory. Modification of one will affect the other.

That being said, it is not completely correct/safe, because the sendbuf may not be appropriately aligned to actually contain a struct ether_header.

Edit: In regard to struct aliasing rules a char* is explicitly allowed to alias any other data type, but the reverse is not necessarily true.