ES6 destructuring assignment with more than one variable type

Question

I have a function that returns 5 objects, and I would like to declare 4 of them using const and 1 of them using let. If I wanted all objects declar

Answer 1

It isn't possible to perform a destructure that initialises both let and const variables simultaneously. However the assignments to const can be reduced to another destructure:

const results = yield getResults()

const { thing1, thing2, thing3, thing4 } = results

let thing5 = results.thing5

Answer 2

You still can use destructuring separately:

const results = yield getResults();
const { thing1, thing2, thing3, thing4} = results;
let   { thing5 } = results;

Alternatively, it is possible to do

let thing5;
const { thing1, thing2, thing3, thing4 } = { thing5 } = yield getResults();

but I guess that should rather be avoided to reduce the WTF/minute of your code.