Swift. Declaring private functions in internal protocol

Question

How can I achieve something like this (doesn\'t compile):

internal protocol InternalPrivateMix {
    private func doPrivately()
    internal func doInternaly         


        

Answer 1

You can do this:

protocol P {
    func int()
}

extension P {
    func int() {
        print("int()")
        priv()
    }
    private func priv() {
        print("priv()")
    }
}

Which might serve your purpose - I use it.

Answer 2

From Apple's docs it looks like the only way to achieve what you are trying to do is to implement 2 protocols - one internal, and one private, as Apple states "You cannot set a protocol requirement to a different access level than the protocol it supports."