How to check whether an Xml file have processing Instruction
Example
How about:
XmlProcessingInstruction instruction = doc.SelectSingleNode("processing-instruction('xml-stylesheet')") as XmlProcessingInstruction;
You can use FirstChild
property of XmlDocument
class and XmlProcessingInstruction
class:
XmlDocument doc = new XmlDocument();
doc.Load("example.xml");
if (doc.FirstChild is XmlProcessingInstruction)
{
XmlProcessingInstruction processInfo = (XmlProcessingInstruction) doc.FirstChild;
Console.WriteLine(processInfo.Data);
Console.WriteLine(processInfo.Name);
Console.WriteLine(processInfo.Target);
Console.WriteLine(processInfo.Value);
}
Parse Value
or Data
properties to get appropriate values.
How about letting the compiler do more of the work for you:
XmlDocument Doc = new XmlDocument();
Doc.Load(openFileDialog1.FileName);
XmlProcessingInstruction StyleReference =
Doc.OfType<XmlProcessingInstruction>().Where(x => x.Name == "xml-stylesheet").FirstOrDefault();