Is there an easy way to unpack a tuple while using enumerate in loop?

Question

Consider this:

the_data = [\'a\',\'b\',\'c\']

With enumerate this loop can be written as:

  for index,item in enumerate(the         


        

Answer 1

Use this:

for index, (name, sport) in enumerate(the_data.iteritems()):
   pass

This is equivalent to:

>>> a, (b, c) = [1, (2, 3)]
>>> a, b, c
(1, 2, 3)

This is commonly used with zip and enumerate combo as well:

for i, (a, b) in enumerate(zip(seq1, seq2)):
    pass