Why can't the type of my class-static auto function be deduced within the class scope?

Question

I\'m trying to get the return type of an auto function. This works:

auto foo(int bar)
{
    return 0;
}

typedef std::result_of

        

Answer 1

While the way you have written the code makes it appear possible, the in-class definition of foo() can only be processed after the class is fully defined. It is as if you wrote this:

struct Foo
{
    static auto foo(int bar);

    typedef std::result_of<decltype(Foo::foo)> foo_t;
};

auto Foo::foo(int bar)
{
    return 0;
}

The definition of foo() is allowed to use types defined in class Foo, including foo_t, which would be circular. Therefore, the definition of class Foo is not allowed to use the definition of its member functions--only their declarations.

In other words, you assume the code is fully evaluated from the top to the bottom. It is not.