Enter key on EditText hitting onKey twice

Question

I\'ve attached an OnKeyListener to an EditText. I\'ve overrode the onKey handler to capture a KeyEvent.

When a user hits the enter key (either their computer enter

Answer 1

you can filter like this :

object.setOnKeyListener(new OnKeyListener() {

        @Override
        public boolean onKey(View v, int keyCode, KeyEvent event) {

            if (keyCode == KeyEvent.KEYCODE_ENTER && event.getAction() == KeyEvent.ACTION_UP) {
                // do stuff
                return true;
            }

            return false;
        }
    });

idem when you push the key with KeyEvent.ACTION_DOWN

Answer 2

Ahhhh

I think this is happening for key up and key down?

Answer 3

This event is fired by KeyEvent.ACTION_DOWN and KeyEvent.ACTION_UP. I have done debugging and finally I realize that there is an param called KeyEvent event that I never use, then I checked and found the problem.

Answer 4

I had the same issue and the answers above helped me but I am using Xamarin.Android (c#) so it is slightly different syntax.. Here is what worked for me:

MyStringTextBox.KeyPressed += OnEnterKeyPressed;

protected void OnEnterKeyPressed(object sender, View.KeyEventArgs e)
{
    if (e.KeyCode == Keycode.Enter && e.Event.Action == KeyEventActions.Up)
    {
        DoSomething(this, EventArgs.Empty);
    }
    else
    {
        e.Handled = false;
    }
}

This way, the DoSomething() would only be called on hitting Enter Key (Up) only and thus would be fired once. Works and tested on Xamarin.Android

Answer 5

I debugged and what worked for me was that,

editText.setOnKeyListener(View.OnKeyListener { view, i, keyEvent ->
            if (i == KeyEvent.KEYCODE_ENTER && enterAsSend && (keyEvent.action == KeyEvent.ACTION_UP || keyEvent.action == KeyEvent.ACTION_DOWN)) {
                //Do stuff
                }
                return@OnKeyListener true
            }
            false
        })

and checkout your Editext that android:inputType="textNoSuggestions" because the first click of enter key gives us the suggestion from the dictionary.

Answer 6

if (keyCode == KeyEvent.KEYCODE_ENTER && event.getAction()==0) {