Removing all commas from list in Python

Question

My issue: I\'d like to add all the digits in this string \'1.14,2.14,3.14,4.14\' but the commas are causing my sum function to not work correctly.
I figured

Answer 1

You don't want strip, you want split.

The split function will separate your string into an array, using the separator character you pass to it, in your case split(',').

Answer 2

Since there seem to be a pattern in your input list of floats, this one-liner generates it:

>>> sum(map(float, ','.join(map(lambda x:str(x+0.14), range(1,5))).split(',')))
10.559999999999999

And since it doesn't make much sense joining with commas and immediately splitting by commas, here's a little saner piece of code:

>>> sum(map(float, map(lambda x:str(x+0.14), range(1,5))))
10.559999999999999

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And if you actually meant you wanted to sum single digits and not the actual floating-point numbers (although I doubt it since you cast to float in your sample code):

>>> sum(map(int, ''.join(map(lambda x:str(x+0.14), range(1,5))).replace('.', '')))
30

Answer 3

Use this to remove commas and white spaces

a = [1,2,3,4,5]
print(*a, sep = "")

Output:- 12345

Answer 4

I would use the following:

# Get an array of numbers
numbers = map(float, '1,2,3,4'.split(','))

# Now get the sum
total = sum(numbers)

Answer 5

values=input()         
l=values.split(",")   
print(l)

With values=1,2,3,4,5

the result is ['1','2','3','4','5']

Answer 6

You need split not strip.

>>> for c in '1,2,3,4,5,6,7,8,9'.split(","):
    print float(c)

1.0
2.0
3.0
4.0
5.0
6.0
7.0
8.0
9.0

Or if you want a list comprehension:

>>> [float(c) for c in '1,2,3,4,5,6,7,8,9'.split(",")]
[1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0]

And for getting the sum,

>>> sum(map(float, '1,2,3,4,5,6,7,8,9'.split(",")))
45.0