Delay timer after first fire

Question

I have a timer in my application that triggers a certain event:

myTimer =  NSTimer.scheduledTimerWithTimeInterval(10, target: self,
    selector: \"searchFor         


        

Answer 1

One more way to do that is you can use two timers for that like:

var myTimer = NSTimer()
var secondTimer = NSTimer()

After that you can set two timers this way:

myTimer =  NSTimer.scheduledTimerWithTimeInterval(0, target: self,
    selector: "searchForTRuckDrivers", userInfo:nil, repeats: false)
secondTimer =  NSTimer.scheduledTimerWithTimeInterval(10, target: self,
    selector: "searchForTRuckDrivers", userInfo:nil, repeats: true)

You can set first timer with delay 0 which will not repeat again while set another timer with delay 10 and it will repeat again and again.

After that in method you can invalidate first timer this way:

func searchForTRuckDrivers() {        
    if myTimer.valid {
        myTimer.invalidate()
    }
}

This will remove first timer but second timer will call this method with delay.

Hope it will help.

Answer 2

First schedule the timer as you've done.

timer =  NSTimer.scheduledTimerWithTimeInterval(
    10.0, target: self,
    selector: "searchForDrivers:",
    userInfo: nil,
    repeats: true
)

Then, immediately afterwards, fire timer.

timer.fire()

According to the documentation,

You can use this method to fire a repeating timer without interrupting its regular firing schedule. If the timer is non-repeating, it is automatically invalidated after firing, even if its scheduled fire date has not arrived.

See the NSTimer Class Reference for more information.