Custom word boundaries in regular expression

Question

I am trying to match words using a regular expression, but sadly the word boundary character (\\b) does not include enough characters for my taste, so I want to add more. (i

Answer 1

(no need to escape the + in a character class)

The problem is that you use a negative lookahead first whereas you should use a negative lookbehind. Try:

@"(?<![\w+])" + expression + @"(?![\w+])"