Following works, (copy & paste into R)
a=123
plot(1,1)
legend(\'bottomleft\',legend=bquote(theta == .(a)))
I want to have multiple item
In this case, plotmath is not able to coerce the list of calls to expressions.
> cs <- c(bquote(theta == .(a)),bquote(theta == .(a)))
> cs
[[1]]
theta == 123
[[2]]
theta == 123
> sapply(cs, class)
[1] "call" "call"
You can make this work if you coerce to expressions yourself:
> c(as.expression(bquote(theta == .(a))), as.expression(bquote(theta == .(a))))
expression(theta == 123, theta == 123)
> plot(1,1)
> legend('bottomleft',legend= c(as.expression(bquote(theta == .(a))),
+ as.expression(bquote(theta == .(a)))))
Another way is to coerce the original list of calls to expressions using sapply:
plot(1,1)
legend("bottomleft",
sapply(c(bquote(theta == .(a)), bquote(theta == .(a))), as.expression))
To coerce the original list of calls to expressions it is not necessary to use sapply(). It suffices to use as.expression() only for one of the components within the c() construct:
plot(1,1)
legend("bottomleft",
c(as.expression(bquote(theta == .(a))), bquote(theta == .(a))))
c() will then automatically coerce the whole list, to the expression class.