Here\'s a bit of code that might seem like it would work:
#include
#include
enum test { A = 1 };
int main()
{
int max =
The numeric_limits<T> is a regular class template, it is not connected to the compiler in any special way as to find out about user-defined enum types. If you look at the <limits> file, it has the default template definition that returns zeros for everything, and a whole bunch of type-specific specifications for the individual types, returning the right constants.
You can "plug in" your enum into numeric_limits by providing a specification of numeric_limits<test> by yourself. You can copy the one for int from the <limits>, and modify it to suit your needs.
From the C++11 draft:
In 18.3.2.1, about numeric_limits:
Non-arithmetic standard types, such as complex (26.4.2), shall not have specializations.
And an enum is not an arithmetic standard type.
Then, in the non-specialized template:
template<class T> class numeric_limits {
public:
[...]
static constexpr bool is_specialized = false;
static constexpr T max() noexcept { return T(); }
};
That is, the non-specialized max() function returns the default initialized value for that type, that is 0.
For non-specialized versions of the template, max returns T(). You have not written a numeric_limits specialization for your test type, so you get the default implementation.
std::numeric_limits is specialized in the Standard Library "for each arithmetic type, both floating point and integer, including bool" (§18.3.2.1/2).
Your enumeration test is not one of these types, so the primary template is used. Its behavior is specified by §18.3.2.3/1: "The default numeric_limits<T> template shall have all members, but with 0 or false values."
If you want to know the traits of the underlying type of test, you can use underlying_type:
std::numeric_limits<std::underlying_type<test>::type>::max()
Alternatively, you can specialize numeric_limits for test and have it return the values you want. This is not a particularly good idea, though.