Levenshtein distance c# count error type

Question

I found this bit of code that computes Levenshtein\'s distance between an answer and a guess:

int CheckErrors(string Answer, string Guess)
{
    int[,] d = n         


        

Answer 1

Seems like you could add counters for each of the operations:

                if (Answer[i - 1] == Guess[j - 1])
                    d[i, j] = d[i - 1, j - 1];  //no operation
                else
                {
                    int del = d[i-1, j] + 1;
                    int ins = d[i, j-1] + 1;
                    int sub = d[i-1, j-1] + 1;
                    int op = Math.Min(Math.Min(del, ins), sub);
                    d[i, j] = op;
                    if (i == j)
                    {
                        if (op == del)
                            ++deletions;
                        else if (op == ins)
                            ++insertions;
                        else
                            ++substitutions;
                    }
                }