How can I remove a line-feed/newline BEFORE a pattern using sed

Question

The title already states it:

I want to use some linux one liner (e.g. sed)

to transform

Anytext
{

into

Anyt         


        

Answer 1

One way using sed:

sed -ne '$! N; /^.*\n{/ { s/\n//; p; b }; $ { p; q }; P; D' infile

A test. Assuming infile with content:

one
Anytext
{
two
three
{
four
five
{

Output will be:

one
Anytext{
two
three{
four
five{

Answer 2

If the intention is to remove the newline from a \n{ sequence bbe seems to be the simplest tool to use:

bbe -e 's/\n{/{/' infile

Answer 3

Using awk

cat file
one
Anytext
{
two
three
{
four
five
{

awk '{printf (!/^{/&&NR>1?RS:x)"%s",$0} END {print ""}' file
one
Anytext{
two
three{
four
five{

Answer 4

Sure,

sed 'N;s/\n{/{/'

Or a more thorough version:

sed ':r;$!{N;br};s/\n{/{/g'

Here, :r sets a label that we can refer to in order to create a loop;

$!{...} executes the given set of commands for every line except the last one;

N;br are two commands the get executed in the loop: N appends a new line to the pattern space, and br branches back to the label r, completing the loop.

Then you have all of your file in pattern space when you run the final command:

s/\n{/{/g

You can see the difference between the two approaches if you try it on something like

Anytext
{
{
{

Answer 5

This might work for you (GNU sed):

sed ':a;$!{N;/.*\n{/ba};s/\n{/{/g;P;D' file