Partially disable pedantic warnings in gcc within source

Question

I am trying to get gcc to shut up about my usage of binary constants. They make the code more readable, but prevent me from using -pedantic which I

Answer 1

maybe, you could use a macro which can do what you want to achieve in a portable manner. here's a short example:

#include <stdio.h>

#define BINARY(N) strtol(#N, 0, 2)

int main()
{
    unsigned int piece = BINARY(10010101);
    printf("%u\n", piece);

    return 0;
}

in theory, gcc should be able to optimize the calls to strtol away and you don't lose readability.

EDIT: It seems that gcc does NOT optimize the strtol calls away as of now. However, your performance loss should be negligible.

Cheers!

Answer 2

From the gcc manual at: http://gcc.gnu.org/onlinedocs/gcc-4.8.2/gcc/Alternate-Keywords.html#Alternate-Keywords

-pedantic and other options cause warnings for many GNU C extensions. You can prevent such warnings within one expression by writing __extension__ before the expression. __extension__ has no effect aside from this.

I just compiled the following block with -Wall -Wextra -Wpedantic with gcc-4.8.2, and no warning was printed:

static uint8_t shbl[2][9] = {
{ __extension__ 0b11111111,
  __extension__ 0b11111110,
  __extension__ 0b11111100,
  __extension__ 0b11111000,
  __extension__ 0b11110000,
  __extension__ 0b11100000,
  __extension__ 0b11000000,
  __extension__ 0b10000000,
  __extension__ 0b00000000 },
// BLOCK_RIGHT
{ __extension__ 0b11111111,
  __extension__ 0b01111111,
  __extension__ 0b00111111,
  __extension__ 0b00011111,
  __extension__ 0b00001111,
  __extension__ 0b00000111,
  __extension__ 0b00000011,
  __extension__ 0b00000001,
  __extension__ 0b00000000 }
};

(Of course this is ugly, and I'll change that to a precompiler macro. But for a test it was acceptable.)