How can reference the last item in a list in a Django template? {{ list.-1.key }}

Question

if I have a variable in the context of unknown length, for example;
list=[{\'key\':\'A\'},{\'key\':\'B\'},{\'key\':\'C\'}]

How can I get the last ob

Answer 1

without with, will be:

{% set last = list|last %}
{{ last.key }}

Answer 2

Use this piece of code in your template:

{{ list|slice:":-1".items.0.0 }}

Answer 3

You can mark the last forloop by the following tags

{% if forloop.last %} ... {% endif %}

and add you special desire inside the tags.

Answer 4

Use the last template tag:

{{ value|last }}

If value is the list ['a', 'b', 'c', 'd'], the output will be the string "d".

Answer 5

Thanks everyone for you help, it lead me to the realisation that I can use the with tag.

{% with list|last as last %}
    {{ last.key }}
{% endwith %}

Answer 6

In my case I find this solution: {{object_list.last.id}} very useful on expression like this: {% url 'my-url' object_list.first.id object_list.last.id %}