Return values from one script to another script

Question

I have the following script that will run each script (sequentially) in a directory:

import os

directory = []

for dirpath, dirnames, filenames in os.walk(\         


        

Answer 1

You can use the locals argument of execfile(). Write the scripts like this:

def run_script():
    ret_value = 2
    return ret_value

script_ret = run_script()

And in your main script:

script_locals = dict()
execfile("path/to/script", dict(), script_locals)
print(script_locals["script_ret"])

Answer 2

I'm just curious if there is a way to return values so that the parent script can access the data.

This is why you define functions and return values.

Script 1 should include a function.

def main():
    all the various bits of script 1 except the import 
    return x

if __name__ == "__main__":
    x= main()
    print( x )

Works the same as yours, but now can be used elsewhere

Script 2 does this.

import script1
print script1.main()

That's the way one script uses another.

Answer 3

x is local to the script1 function, so it's not visible in the outer scope. If you put the code inside script1 at the top level of the file, it should work.