Excel or R: Preparing time series from multiple sources?

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野性不改 2020-12-31 20:33

Lately I often had to handle time series data from multiple .csv sources in the same analysis. Let\'s assume for simplicity that all series are regular quarterly series (no

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  • 2020-12-31 21:37

    I do this in R all the time. You may find it easier to do in Excel but if your data change, you have to do the same process again. Using R makes it much easier to update and reproduce your results.

    Dealing with monthly or quarterly frequencies are made significantly easier with zoo's yearmon and yearqtr index classes, respectively. Once you have your data in zoo objects with yearqtr indexes, all you have to do is merge all the objects.

    Here's your sample data:

    Lines1 <-
    "27.05.11;5965.95
    26.05.11;5947.06
    25.05.11;5942.82
    24.05.11;5939.98"
    f1 <- read.csv2(con <- textConnection(Lines1), header=FALSE)
    close(con)
    
    Lines2 <-
    "Germany;Switzerland;USA;OECDEurope
    69,90974;61,8241;55,60966;64,96157
    67,0394;62,18966;56,47361;64,15152
    70,56651;63,6347;56,87237;65,43568"
    f2 <- read.csv2(con <- textConnection(Lines2), header=TRUE)
    close(con)
    
    Lines3 <-
    "1984-04-01,33.3238396624473
    1984-07-01,63.579833082501
    1984-10-01,35.8375401560349"
    f3 <- read.csv(con <- textConnection(Lines3), header=FALSE)
    close(con)
    

    The example below assumes the starting date for the first file is 1984Q2 and the starting date for the second file is 1984Q4. You can see that merge.zoo takes care of aligning all the dates for you. After everything is aligned in your zoo object, you can use the as.ts method to create a mts object.

    z1 <- zoo(f1[,-1], as.Date(f1[,1], "%d.%m.%y"))
    z2 <- zoo(f2, as.yearqtr("1984Q4")+(seq_len(NROW(f1))-1)/4)
    z3 <- zoo(f3[,-1], as.yearqtr(as.Date(f3[,1])))
    
    library(xts)
    # Use xts::apply.quarterly to aggregate series with higher periodicity.
    # Here I just take the last obs but you could use another function (e.g. mean).
    z1 <- apply.quarterly(z1, last)
    index(z1) <- as.yearqtr(index(z1))  # convert the index to yearqtr
    
    (Z <- merge(z1,z2,z3))
    #         z1      Germany  Switzerland USA      OECDEurope z3
    # 1984 Q2 <NA>    <NA>     <NA>        <NA>     <NA>       33.32383
    # 1984 Q3 <NA>    <NA>     <NA>        <NA>     <NA>       63.57983
    # 1984 Q4 <NA>    69.90974 61.8241     55.60966 64.96157   35.83754
    # 1985 Q1 <NA>    67.0394  62.18966    56.47361 64.15152   <NA>
    # 1985 Q2 <NA>    70.56651 63.6347     56.87237 65.43568   <NA>
    # 1985 Q3 <NA>    69.90974 61.8241     55.60966 64.96157   <NA>
    # 2011 Q2 5965.95 <NA>     <NA>        <NA>     <NA>       <NA>
    
    # Note that ts will create an object with a observation for every period,
    # even if all the columns are missing.
    TS <- as.ts(Z)
    
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  • 2020-12-31 21:37

    My strategy for problems of this type is:

    1. Read each data source into a standard data.frame
    2. Clean each data.frame, i.e. get data into desired format, process missing values, etc.
    3. Merge or join into standard data.frame
    4. Perform any aggregate data cleanup, e.g. adding blank lines, removing duplicates, etc.
    5. Only then pass data to the next step, such as conversion to ts object, plot it, etc.

    Using your example data:

    v1 <- "27.05.11;5965.95
    26.05.11;5947.06
    25.05.11;5942.82
    24.05.11;5939.98"
    
    v2 <- "Germany;Switzerland;USA;OECDEurope
    69,90974;61,8241;55,60966;64,96157
    67,0394;62,18966;56,47361;64,15152
    70,56651;63,6347;56,87237;65,43568"
    
    
    v3 <- "1984-04-01,33.3238396624473
    1984-07-01,63.579833082501
    1984-10-01,35.8375401560349"
    
    # Read and clean data
    dat1 <- read.table(textConnection(v1), header=FALSE, sep=";", dec=".")
    names(dat1) <- c("date", "V1")
    dat1$date <- as.Date(dat1$date, format="%d.%m.%y")
    dat1
    
    dat2 <- read.table(textConnection(v2), header=TRUE, sep=";", dec=",")
    dat2$date <- seq(as.Date("2011/1/1"), by="3 months", length.out=3)
    dat2
    
    dat3 <- read.table(textConnection(v3), header=FALSE, sep=",", dec=".")
    names(dat3) <- c("date", "V2")
    dat3$date <- as.Date(dat3$date)
    dat3
    
    # Merge separate data.frames.
    # I use join() in package plyr, you may wish to use merge(), rbind.fill, etc
    library(plyr)
    join(join(dat1, dat2, type="full"), dat3, type="full")
    

    The results:

             date      V1  Germany Switzerland      USA OECDEurope       V2
    1  2011-05-27 5965.95       NA          NA       NA         NA       NA
    2  2011-05-26 5947.06       NA          NA       NA         NA       NA
    3  2011-05-25 5942.82       NA          NA       NA         NA       NA
    4  2011-05-24 5939.98       NA          NA       NA         NA       NA
    5  2011-01-01      NA 69.90974    61.82410 55.60966   64.96157       NA
    6  2011-04-01      NA 67.03940    62.18966 56.47361   64.15152       NA
    7  2011-07-01      NA 70.56651    63.63470 56.87237   65.43568       NA
    8  1984-04-01      NA       NA          NA       NA         NA 33.32384
    9  1984-07-01      NA       NA          NA       NA         NA 63.57983
    10 1984-10-01      NA       NA          NA       NA         NA 35.83754
    
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