How to redirect preserving original referrer field?

Question

I have the following PHP redirect script:

if ($country==\"IL\") { header(\'Location: http://iquality.itayb.net/index-he.html\'); }
else { header(\'Location:          


        

Answer 1

You can not use header('Referer: SOME_REFERER_URL') because browser will overwrite it anyway.

If you own redirected targets iquality.itayb.net then there are several ways to do this:

1. Save referer in the user session.

   // in your first script save real referer to session
   $_SESSION['REAL_REFERER'] = $_SERVER['HTTP_REFERER'];
   
   // in the redirected script extract referer from session
   $referer = '';
   if (isset($_SESSION['REAL_REFERER'])) {
       $referer = $_SESSION['REAL_REFERER'];
       unset($_SESSION['REAL_REFERER']);
   }
   else {
       $referer = $_SERVER['HTTP_REFERER'];
   }
   

2. Send referer as parameter:

   // in your first script
   header('Location: http://iquality.itayb.net/index-he.html?referer=' . $_SERVER['HTTP_REFERER']);
   
   // in your refered script extract from the parameter
   $referer = '';
   if (isset($_REQUEST['referer'])) {
       $referer = $_REQUEST['referer'];
   }
   else {
       $referer = $_SERVER['HTTP_REFERER'];
   }
   

If you want to cheat any other server then use something like this:

$host = 'www.yourtargeturl.com';
$service_uri = '/detect_referal.php';
$vars ='additional_option1=yes&additional_option2=un';

$header = "Host: $host\r\n";
$header .= "User-Agent: PHP Script\r\n";
$header .= "Content-Type: application/x-www-form-urlencoded\r\n";
$header .= "Referer: {$_SERVER['HTTP_REFERER']} \r\n";
$header .= "Content-Length: ".strlen($vars)."\r\n";
$header .= "Connection: close\r\n\r\n";

$fp = fsockopen("".$host,80, $errno, $errstr);
if (!$fp) {
  echo "$errstr ($errno)<br/>\n";
  echo $fp;
} else {
    fputs($fp, "POST $service_uri  HTTP/1.1\r\n");
    fputs($fp, $header.$vars);
    fwrite($fp, $out);

    while (!feof($fp)) {
        echo fgets($fp, 128);
    }
    fclose($fp);
}