Find/Replace but Increment Value

Question

I have an .HTML file that has many photos attached to it for displaying a photo gallery. I\'m replacing old photos with new ones, and I\'m thinking there must be a more inte

Answer 1

OK, I came up with a Notepad++ solution.
It does require you to install the Notepad++ plugin PythonScript. It is a TextPad-like incremental replace.

i.e.
Search and replace integer values within a string
replacing incrementally starting with 1 (0 is the default starting value):

In your case it would be
Search: ...images/69thStreet[0-9]+.jpg
Replace: ...images/xyz00\i(1).jpg

Install the PythonScript plugin.
Save the code below as a PythonScript and associate a shortcut (i.e. Ctrl+i) to it:
Then open your html file in Notepad++ and run the script below on your html file.
When prompted by the search replace dialogue, enter the following 2 lines:
...images/69thStreet[0-9]+.jpg
...images/xyz00\i(1).jpg

Now, all instances of
...images/69thStreet010.jpg
...images/69thStreet011.jpg
...images/69thStreet012.jpg

will become
...images/xyz001.jpg
...images/xyz002.jpg
...images/xyz003.jpg

Here is the PythonScript code

from Npp import *
import re, string

# First we'll start an undo action, then Ctrl-Z will undo the actions of the whole script
editor.beginUndoAction()

expression     = notepad.prompt("Enter the search string on the first line, followed by Ctrl+Enter, \n" +
                                "followed by the replace string on second line",
                                "Incremental Search/Replace" ,
                                "")

expressionList = re.split(r"[\n\r]+", expression)

if len(expressionList) == 2:
    foundCount = [0]

    def incrementalReplace(parmReplaceStr,parmFoundCount):
        varPatternI  = r'\\i\((?P<starting>[0-9]+)\)'
        varPatternIi = r'\\i'
        varPatternISearch = re.search(varPatternI , parmReplaceStr)

        if varPatternISearch != None:
            varFoundCount    = int(varPatternISearch.group('starting')) + parmFoundCount[0]
            varReplaceString = re.sub(varPatternI ,str(varFoundCount    ),parmReplaceStr)
        elif re.search(varPatternIi, parmReplaceStr) != None:
            varReplaceString = re.sub(varPatternIi,str(parmFoundCount[0]),parmReplaceStr)

        parmFoundCount[0] = parmFoundCount[0] + 1    
        return varReplaceString

    # Do a Python regular expression replace
    editor.searchAnchor()
    while editor.searchNext(0x00200000,expressionList[0]) != -1:
        editor.replaceSel(incrementalReplace(expressionList[1],foundCount))
        editor.lineDown() 
        editor.searchAnchor()

    # End the undo action, so Ctrl-Z will undo the above two actions
    editor.endUndoAction()