Bash case statement

Question

I\'m trying to learn case as I was to write a fully functional script.

I\'m starting off with the below

#!/bin/sh
case $@ in

    -h|--help)
                 


        

Answer 1

Try this

#!/bin/sh

usage() {
    echo `basename $0`: ERROR: $* 1>&2
    echo usage: `basename $0` '[-a] [-b] [-c] 
        [file ...]' 1>&2
    exit 1
}


while :
do
    case "$1" in
    -a|-A) echo you picked A;;
    -b|-B) echo you picked B;;
    -c|-C) echo you picked C;;
    -*) usage "bad argument $1";;
    *) break;;
    esac
    shift
done

Answer 2

Using getopt or getopts is the better solution. But to answer your immediate question, $@ is all of your arguments, so -h -c, which doesn't match any of the single-argument patterns in your case statement. You would still need to iterate over your arguments like so

for arg in "$@"; do
    case $arg in
       ....
    esac
done

Answer 3

to parse the positional arguments like ... $1 , just use $1 in the case stmt and then at the end ... use shift to pust the 2nd arg to $1 and likewise .

also i would put the case stmt in a while loop or better a fxn so that i can run it twice for the two options or the number of options ..........

$# will let you know how many options/arguments were there .