How to write list of strings to file, adding newlines?

Question

def generator():
    nums = [\'09\', \'98\', \'87\', \'76\', \'65\', \'54\', \'43\']
    s_chars = [\'*\', \'&\', \'^\', \'%\', \'$\', \'#\', \'@\',]

    data =         


        

Answer 1

Change

data.write(c + n)

to

data.write("%s%s\n" % (c, n))

Answer 2

A properly-placed data.write('\n') will handle that. Just indent it appropriately for the loop you want to punctuate.

Answer 3

Python's print is the standard "print with newline" function.

Therefore, you can directly do, if you use Python 2.x:

print  >> data, c+n

If you use Python 3.x:

print(c+n, file=data)

Answer 4

def generator():
     nums = ['09', '98', '87', '76', '65', '54', '43']
     s_chars = ['*', '&', '^', '%', '$', '#', '@',]

     data = open("list.txt", "w")
     for c in s_chars:
        for n in nums:
           data.write(c + n + "\n")
     data.close()

OR

def generator():
     nums = ['09', '98', '87', '76', '65', '54', '43']
     s_chars = ['*', '&', '^', '%', '$', '#', '@',]

     data = open("list.txt", "w")
     for c in s_chars:
        for n in nums:
           data.write(c + n)
        data.write("\n")
     data.close()

depending on what you want.

Answer 5

As other answers gave already pointed out, you can do it by appending a '\n' to c+n or by using the format string "%s%s\n".

Just as a matter of interest, I think it would be more pythonic to use a list comprehension instead of two nested loops:

data.write("\n".join("%s%s"%(c,n) for c in s_chars for n in nums))

Answer 6

In the previously reply, I have made a wrong answer because I have misunderstood the requirements, please ignore it.

I think you can use join to simplify the inner loop

data = open("list.txt", "w")
for c in s_chars:
    data.write("%s%s\n" % (c, c.join(nums)))
data.close()