Java XOR over two arrays [closed]

Answer 1

Would this be a good solution? (I wrote this thanks to what you gave me)

if(array1.length==array2.length){
  for(int i=0;i<array1.length;i++){

    output.add(logicalXOR(array1.get(i),array2.get(i)))

  }
}

Of course array1,2 and output would be arrayLists

Answer 2

If you are storing these numbers in byte arrays, use this straightforward solution:

byte[] array_1 = new byte[] { 1, 0, 1, 0, 1, 1 };
byte[] array_2 = new byte[] { 1, 0, 0, 1, 0, 1 };

byte[] array_3 = new byte[6];

int i = 0;
for (byte b : array_1)
    array_3[i] = b ^ array_2[i++];

Output array:

0 0 1 1 1 0