Is there a built-in way to convert IEnumerator to IEnumerable?
This is a variant I have written... The specific is a little different. I wanted to do a MoveNext() on an IEnumerable<T>, check the result, and then roll everything in a new IEnumerator<T> that was "complete" (so that included even the element of the IEnumerable<T> I had already extracted)
// Simple IEnumerable<T> that "uses" an IEnumerator<T> that has
// already received a MoveNext(). "eats" the first MoveNext()
// received, then continues normally. For shortness, both IEnumerable<T>
// and IEnumerator<T> are implemented by the same class. Note that if a
// second call to GetEnumerator() is done, the "real" IEnumerator<T> will
// be returned, not this proxy implementation.
public class EnumerableFromStartedEnumerator<T> : IEnumerable<T>, IEnumerator<T>
{
public readonly IEnumerator<T> Enumerator;
public readonly IEnumerable<T> Enumerable;
// Received by creator. Return value of MoveNext() done by caller
protected bool FirstMoveNextSuccessful { get; set; }
// The Enumerator can be "used" only once, then a new enumerator
// can be requested by Enumerable.GetEnumerator()
// (default = false)
protected bool Used { get; set; }
// The first MoveNext() has been already done (default = false)
protected bool DoneMoveNext { get; set; }
public EnumerableFromStartedEnumerator(IEnumerator<T> enumerator, bool firstMoveNextSuccessful, IEnumerable<T> enumerable)
{
Enumerator = enumerator;
FirstMoveNextSuccessful = firstMoveNextSuccessful;
Enumerable = enumerable;
}
public IEnumerator<T> GetEnumerator()
{
if (Used)
{
return Enumerable.GetEnumerator();
}
Used = true;
return this;
}
IEnumerator IEnumerable.GetEnumerator()
{
return GetEnumerator();
}
public T Current
{
get
{
// There are various school of though on what should
// happens if called before the first MoveNext() or
// after a MoveNext() returns false. We follow the
// "return default(TInner)" school of thought for the
// before first MoveNext() and the "whatever the
// Enumerator wants" for the after a MoveNext() returns
// false
if (!DoneMoveNext)
{
return default(T);
}
return Enumerator.Current;
}
}
public void Dispose()
{
Enumerator.Dispose();
}
object IEnumerator.Current
{
get
{
return Current;
}
}
public bool MoveNext()
{
if (!DoneMoveNext)
{
DoneMoveNext = true;
return FirstMoveNextSuccessful;
}
return Enumerator.MoveNext();
}
public void Reset()
{
// This will 99% throw :-) Not our problem.
Enumerator.Reset();
// So it is improbable we will arrive here
DoneMoveNext = true;
}
}
Use:
var enumerable = someCollection<T>;
var enumerator = enumerable.GetEnumerator();
bool res = enumerator.MoveNext();
// do whatever you want with res/enumerator.Current
var enumerable2 = new EnumerableFromStartedEnumerator<T>(enumerator, res, enumerable);
Now, the first GetEnumerator() that will be requested to enumerable2 will be given through the enumerator enumerator. From the second onward the enumerable.GetEnumerator() will be used.
You could use the following which will kinda work.
public class FakeEnumerable<T> : IEnumerable<T> {
private IEnumerator<T> m_enumerator;
public FakeEnumerable(IEnumerator<T> e) {
m_enumerator = e;
}
public IEnumerator<T> GetEnumerator() {
return m_enumerator;
}
// Rest omitted
}
This will get you into trouble though when people expect successive calls to GetEnumerator to return different enumerators vs. the same one. But if it's a one time only use in a very constrained scenario, this could unblock you.
I do suggest though you try and not do this because I think eventually it will come back to haunt you.
A safer option is along the lines Jonathan suggested. You can expend the enumerator and create a List<T> of the remaining items.
public static List<T> SaveRest<T>(this IEnumerator<T> e) {
var list = new List<T>();
while ( e.MoveNext() ) {
list.Add(e.Current);
}
return list;
}