I have this code where I just want to set a environment variable:
package main
import (
\"os\"
\"fmt\"
)
func main() {
_ = os.Setenv(\"FOO\", \
When a new process is created, the environment of the parent process is copied. Changes to the environment in the new process do not affect the parent process. You would have to have your program start a shell after modifying the environment.
Not sure this is ultimately what you want to do, but it does give you the result you asked for.
package main
import (
"os"
"syscall"
)
func main() {
os.Setenv("FOO", "BAR")
syscall.Exec(os.Getenv("SHELL"), []string{os.Getenv("SHELL")}, syscall.Environ())
}
This replaces the go process with a new shell with the modified environment.
You probably would want to call it as "exec APPNAME", as that will avoid having a shell in a shell.
example:
#!/bin/bash
exec go-env-setter-app
you will end up with a bash shell with the modified environment