How to determined if a 2 dimensional list contain a value?

Question

I have a list like following

mylist = [(\'value1\', \'value2\', \'value3\'), (\'secval1\', \'secval2\', \'secval3\')]

how do I see if the l

Answer 1

Use any():

any('value2' in sublist for sublist in mylist)

Answer 2

similar to any(), a solution that also supports short-circuiting :

>>> from itertools import chain
>>> mylist = [('value1', 'value2', 'value3'), ('secval1', 'secval2', 'secval3')]
>>> 'value2' in chain(*mylist)
True

proof that it short-circuits like any():

>>> it=chain(*mylist)
>>> 'value2' in it
True
>>> list(it) #part of iterable still not traversed
['value3', 'secval1', 'secval2', 'secval3']

Answer 3

You can simply check all sublists with any:

any('value2' in subl for subl in mylist)

Answer 4

'value2' in (item for sublist in mylist for item in sublist)