Regular expression include and exclude special characters

Question

I\'m finding a regular expression which adheres below rules.

Allowed Characters

Alphabet : a-z / A-Z
Numbers : 0-9
Special Characters : ~ @ # $ ^ &

Answer 1

For the allowed characters you can use

^[a-zA-Z0-9~@#$^*()_+=[\]{}|\\,.?: -]*$

to validate a complete string that should consist of only allowed characters. Note that - is at the end (because otherwise it'd be a range) and a few characters are escaped.

For the invalid characters you can use

[<>'"/;`%]

to check for them.

To combine both into a single regex you can use

^(?=[a-zA-Z0-9~@#$^*()_+=[\]{}|\\,.?: -]*$)(?!.*[<>'"/;`%])

but you'd need a regex engine that allows lookahead.

Answer 2

[a-zA-Z0-9~@#\^\$&\*\(\)-_\+=\[\]\{\}\|\\,\.\?\s]*

This would do the matching, if you only want to allow that just wrap it in ^$ or any other delimiters that you see appropriate, if you do this no specific disallow logic is needed.

Answer 3

You haven't actually asked a question, but assuming you have one, this could be your answer...

Assuming all characters, except the "Special Characters" are allowed you can write

String regex = "^[^<>'\"/;`%]*$";