How to make “int” parse blank strings?

Question

I have a parsing system for fixed-length text records based on a layout table:

parse_table = [\\
    (\'name\', type, length),
    ....
    (\'numeric_field\         


        

Answer 1

Use a factory function instead of int or a subclass of int:

def mk_int(s):
    s = s.strip()
    return int(s) if s else 0

Answer 2

Use int() function with the argument s.strip() or 0, i.e:

int(s.strip() or 0)

Or if you know that the string will always contain only digit characters or is empty (""), then just:

int(s or 0)

Answer 3

lenient_int = lambda string: int(string) if string.strip() else None
                                                          #else 0
                                                          #else ???

Answer 4

note that mylist is a list that contain:

Tuples, and inside tuples, there are I) null / empty values, ii) digits, numbers as strings, as well iii) empty / null lists. for example:

mylist=[('','1',[]),('',[],2)]

@Arlaharen I am repeating here, your solution, somewhat differently, in order to add keywords, because, i lost a lot of time, in order to find it!

The following solution is stripping / converting null strings, empty strings, or otherwise, empty lists, as zero, BUT keeping non empty strings, non empty lists, that include digits / numbers as strings, and then it convert these strings, as numbers / digits.

Simple solution. Note that "0" can be replaced by iterable variables. Note the first solution cannot TREAT empty lists inside tuples.

int(mylist[0][0]) if mylist[0][0].strip() else 0

I found even more simpler way, that IT can treat empty lists in a tuple

int(mylist[0][0] or '0')

convert string to digits / convert string to number / convert string to integer strip empty lists / strip empty string / treat empty string as digit / number convert null string as digit / number / convert null string as integer