Is it possible to find the present index in an enhanced for loop? [duplicate]

Answer 1

Is it possible to find the present index in an enhanced for loop?

For getting the index, you can use List.indexOf(object).

I have used these techniques for getting index of current object in a list. For example you given above, the removal can be done using two ways.

• Using object instance to remove object.

 public boolean cancelTicket(Flight f, Customer c) {
        List<BookingDetails> l = c.getBooking();
        if (l.size() < 0) {
            return false;
        } else {
            for (BookingDetails bd : l) {
                if(bd.getFlight()==f){
                    l.remove(bd)  // Object Instance here..
                }
            }
        }
    }

• Using List.indexOf(index)

 public boolean cancelTicket(Flight f, Customer c) {
        List<BookingDetails> l = c.getBooking();
        if (l.size() < 0) {
            return false;
        } else {
            for (BookingDetails bd : l) {
                if(bd.getFlight()==f){
                    l.remove(l.indexOf(bd))  // index Number here..
                }
            }
        }
    }

Answer 2

Yes, Use a counter before the for statement. as such:

int i = 0;
for (int s : ss)
{
   // Some Code
   System.out.println(i);

   i++;
}

Answer 3

Is it possible to find the present index in an enhanced for loop?

No. If you need the index, I suggest you use an ordinary for-loop.

However, you don't actually seem to need the index in this situation. Unless you're dealing with some really strange type of list, you could go with an Iterator and use the Iterator.remove() method, like this:

public boolean cancelTicket(Flight f, Customer c) {
    Iterator<BookingDetails> bdIter = c.getBooking().iterator();

    if (!bdIter.hasNext())
        return false;

    while (bdIter.hasNext())
        if (bdIter.next().getFlight() == f)
            bdIter.remove();

    return true;
}