I have two files main.go which is under package main, and another file with some functions in the package called functions.
My question is:
Export function getValue by making 1st character of function name capital, GetValue
You import the package by its import path, and reference all its exported symbols (those starting with a capital letter) through the package name, like so:
import "MyProj/functions"
functions.GetValue()
you can write
import(
functions "./functions"
)
func main(){
c:= functions.getValue() <-
}
If you write in gopath write this import functions "MyProj/functions" or if you are working with Docker
You should prefix your import in main.go with: MyProj, because, the directory the code resides in is a package name by default in Go whether you're calling it main or not. It will be named as MyProj.
package main just denotes that this file has an executable command which contains func main(). Then, you can run this code as: go run main.go. See here for more info.
You should rename your func getValue() in functions package to func GetValue(), because, only that way the func will be visible to other packages. See here for more info.
File 1: main.go (located in MyProj/main.go)
package main
import (
"fmt"
"MyProj/functions"
)
func main(){
fmt.Println(functions.GetValue())
}
File 2: functions.go (located in MyProj/functions/functions.go)
package functions
// `getValue` should be `GetValue` to be exposed to other packages.
// It should start with a capital letter.
func GetValue() string{
return "Hello from this another package"
}
In Go packages, all identifiers will be exported to other packages if the first letter of the identifier name starts with an uppercase letter.
=> change getValue() to GetValue()