C#: bitwise operator in enum (Custom Authorization in MVC)

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旧巷少年郎
旧巷少年郎 2020-12-29 14:27

I\'m currently reading an article , but I do not really understand how this work with the logical operator. Can anyone explain this to me?

eg. If I want to have 4 le

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  • 2020-12-29 14:42

    This example uses the bitwise shift operator: "<<". This operator takes the bits and shifts them. For example, "1 << 3" results in the number 8. So, in binary,

    customer =    0001
    employee =    0010
    supervisor =  0100
    admin =       1000 (I think this was supposed to read 1 << 3)
    

    Now, you can assign people multiple roles using the bitwise-or operator. This would be a single vertical-bar "|". The bitwise or combines the two numbers bit-by-bit, setting each bit that is set in either of the two operands.

    myRole = customer | employee = 0011
    

    The if-statement you have is intended to tell whether someone has a particular role. It uses bitwise-and: "&". Bitwise-and combines the two numbers, setting a bit only if the bit is set in both the operands.

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  • 2020-12-29 14:47

    They're using an enum as a bit map: if a specific bit is set, so you have that privilege. They're also using a left shift operator. Let me try to demonstrate all that at once:

    Role         Decimal   Binary   Shifted   Decimal
    --------     -------   ------   -------   -------
    Customer   =    1    = 000001 = 000001  =    1
    Employee   =    1    = 000001 = 000010  =    2
    Supervisor =    1    = 000001 = 000100  =    4
    Admin      =    2    = 000010 = 010000  =   16
    

    This way you can combine two roles. For instance, some user can play Employee and Supervisor at same time, just having correspondent bits set.

    And how to check if a bit is set? It's exactly what that (Roles & role) != role) do. For example:

    WebRoles user = WebRoles.Employee | WebRoles.Supervisor;
    bool isEmployee = (user & WebRoles.Employee) == WebRoles.Employee; // true
    

    If you test user variable to check if that Employee bit is set, that & operator will return all match bits.

    Hope this help; feel free to edit this answer

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