Regex for website or url validation [duplicate]

Answer 1

You can try this:

^((ftp|http|https):\/\/)?(www.)?(?!.*(ftp|http|https|www.))[a-zA-Z0-9_-]+(\.[a-zA-Z]+)+((\/)[\w#]+)*(\/\w+\?[a-zA-Z0-9_]+=\w+(&[a-zA-Z0-9_]+=\w+)*)?$

Updated Demo

const regex = /^((ftp|http|https):\/\/)?(www.)?(?!.*(ftp|http|https|www.))[a-zA-Z0-9_-]+(\.[a-zA-Z]+)+((\/)[\w#]+)*(\/\w+\?[a-zA-Z0-9_]+=\w+(&[a-zA-Z0-9_]+=\w+)*)?$/gm;
const str = `http://www.sample.com
https://www.sample.com
http://www.sample.com/xyz
www.sample.com
www.sample.com/xyz/#/xyz
sample.com
www.sample.com
mofiz.com
kolim.com
www.murikhao.www.sample.com
http://murihao.www.sample.com
http://www.sample.com/xyz?abc=dkd&p=q&c=2
www.sample.gov.bd
www.sample.com.en
www.sample.vu


`;
let m;

while ((m = regex.exec(str)) !== null) {

    if (m.index === regex.lastIndex) {
        regex.lastIndex++;
    }
    console.log("matched :"+m[0]);
}

Answer 2

Use the regex ^((https?|ftp|smtp):\/\/)?(www.)?[a-z0-9]+\.[a-z]+(\/[a-zA-Z0-9#]+\/?)*$

This is a basic one I build just now. A google search can give you more.

Here

• ^ Should start with
• ((https?|ftp|smtp)://)? may or maynot contain any of these protocols
• (www.)? may or may not have www.
• [a-z0-9]+(.[a-z]+) url and domain and also subdomain if any upto 2 levels
• (/[a-zA-Z0-9#]+/?)*/? can contain path to files but not necessary. last may contain a /
• $ should end there

var a=["http://www.sample.com","https://www.sample.com/","https://www.sample.com#","http://www.sample.com/xyz","http://www.sample.com/#xyz","www.sample.com","www.sample.com/xyz/#/xyz","sample.com","sample.com?name=foo","http://www.sample.com#xyz","http://www.sample.c"];
var re=/^((https?|ftp|smtp):\/\/)?(www.)?[a-z0-9]+(\.[a-z]{2,}){1,3}(#?\/?[a-zA-Z0-9#]+)*\/?(\?[a-zA-Z0-9-_]+=[a-zA-Z0-9-%]+&?)?$/;
a.map(x=>console.log(x+" => "+re.test(x)));